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5r^2-6r-56=0
a = 5; b = -6; c = -56;
Δ = b2-4ac
Δ = -62-4·5·(-56)
Δ = 1156
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$r_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$r_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1156}=34$$r_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-6)-34}{2*5}=\frac{-28}{10} =-2+4/5 $$r_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-6)+34}{2*5}=\frac{40}{10} =4 $
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